withThe equations are
x = 2y - 4 (1)
x + 8y = 16. (2)
We will substitute x in equation (2) by equation (1)
(2y - 4) + 8y = 16
2y - 4 + 8y = 16
Add the like terms in the left side
(2y + 8y) - 4 = 16
10y - 4 = 16
Now we will solve this equation to find y
Add 4 to both sides
10y - 4 + 4 = 16 + 4
10y = 20
Divide both sides by 10 to find y
10y/10 = 20/10
y = 2
Now substitute y by 2 in equation (1) to find x
x = 2(2) - 4
x = 4 - 4
x = 0
The solution of the system of equations is (0, 2)
The coordinates are (0, 2)