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What is the distance ab rounded to the nearest tenth when a=(-1,2) and b=(1,-2).

User Overblade
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1 Answer

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18 votes

Answer

Step-by-step explanation

The distance between two points with the coordinates a(x₁, y₁) and b(x₂, y₂) is given as

ab = √[(x₂ - x₁)² + (y₂ - y₁)²]

a(x₁, y₁) and b(x₂, y₂) = a (-1, 2) and b (1, -2)

x₂ = 1

x₁ = -1

y₂ = -2

y₁ = 2

ab = √[(x₂ - x₁)² + (y₂ - y₁)²]

ab = √[(1 - (-1))² + (-2 - 2)²]

ab = √[(1 + 1)² + (-2 - 2)²]

ab = √[(2)

User Ramin Ar
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