Question

What are the quotient and remainder when 6x3 + 13x2 + x − 2 is divided by x − 1?

Answer 1

notice, the divisor is x - 1, thus x - 1 = 0, thus x = 1

doing a quick synthetic division on it,


`\bf \begin{array}l 1&&6&13&1&-2\\ &&&6&19&20\\ --&&-&--&--&--\\ &&6&19&20&\boxed{18}&\impliedby remainder \end{array} \\\\\\ 6x^2+19x+20`