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What is the destiny of oxygen (O2) at 400 K and a pressure of 3 atm?

User Torsten
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1 Answer

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In this question, we have to find the density of a gas, and we can use the Ideal gas Law to find it, but we need to make a few changes to the formula, the initial formula is:

PV = nRT

Where:

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

But as we can see, there are some missing informations in order to use this formula, and density is mass/volume, so we need to use the ideal gas formula to find mass/volume

One thing we can do is to convert n (number of moles) into mass/molar mass, which is exactly what number moles means, therefore the formula would be:

PV = m/MM * R * T

Now we have mass, and volume, but they are separated in the formula, we need to bring these two together, let's do it mathematically:

PV = m/MM * R * T

P * MM/R * T = m/V, here we have mass/volume, which is exactly density, now we use the informations available to finally find the answer

For this formula we have:

P = 3 atm

MM = for O2 is 32g/mol

R = gas constant is 0.082

T = 400 K

m/V = 3 * 32/0.082 * 400

m/V = 96/32.8

m/V = 2.93 g/L

User WhatsInAName
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