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What is the solution to log2(9x)-log2^3=3?

User TheMomax
by
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2 Answers

0 votes

Answer: B or option two on edg

X = 8/3

Explanation:

User LarsJK
by
8.7k points
3 votes

Answer:


x = (8)/(3) is the solution to
\log_2 9x - \log_2 3 = 3

Explanation:

Using the logarithmic rules:


\log (m)/(n) = \log m -\log n

if
\log_b x = a then;


x = b^a

Given the equation:


\log_2 9x - \log_2 3 = 3

Solve for x:

Apply the logarithmic rules:


\log_2 (9x)/(3) = 3


\log_2  3x = 3

Apply the logarithmic rules;


3x = 2^3


3x = 8

Divide both sides by 3 we have;


x = (8)/(3)

Therefore, the solution for the given equations is,
x = (8)/(3)

User Abbas Jafari
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7.9k points