Question

A certain gas is held at 147 kPa inside a sealed container. If the container is filled with 2.10 moles of thegas at 340.0 K, what is the volume of this container?___ L

Answer 1

Step 1

The gas is assumed to be ideal. Therefore, the next formula is applied:

`p\text{ x V = n x R x T \lparen1\rparen}`

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Step 2

Information provided:

p = pressure = 147 kPa x (1000 Pa/1 kPa) = 147000 Pa

V = volume = unknown

n = number of moles = 2.10 moles

T = absolute temperature = 340.0 K

R = gas constant = 8.314 m^3 x Pa/mol K (according to the variables and units provided)

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Step 3

Procedure:

V is found from (1):

`\begin{gathered} V\text{ = }\frac{n\text{ x R x T}}{p} \\ V\text{ = }\frac{2.10\text{ moles x 8.314 }\frac{m^3Pa}{mol\text{ K}}x340.0\text{ K}}{147000\text{ Pa}} \\ V\text{ = 0.0403 m}^3 \end{gathered}`

Next, V = 0.0403 m^3 x (1000 L/1 m^3) = 40.3 L

Answer: V = volume = 40.3 L