Question

Hello! I need some assistance with this homework question for precalculus, please?HW Q30

Answer 1

`\begin{equation*} 2\log_3z \end{equation*}`

Step-by-step explanation:

Given the below logarithmic expression;

`log_3z^2`

To simplify the above, we'll have to apply the below power rule of logarithm rule;

`log_am^n=nlog_am`

Applying the above logarithm rule, we'll have;

`\log_3z^2=2\log_3z`