Question

Magnesium metal reacts with iodine gas at high temperatures to form magnesium iodide. what mass of mgi2 can be produced from the reaction of 5.15 g mg and 50.0 g i2

Answer 1

To find the mass of MgI2 produced in the reaction between Mg and I2, you need to calculate the moles of Mg and I2 and use the mole ratio from the balanced equation. Finally, convert the moles of MgI2 to grams using the molar mass of MgI2.

Step-by-step explanation:

In this reaction, the balanced equation is 2Mg + I2 → 2MgI2. From the balanced equation, we can see that 2 moles of Mg react with 1 mole of I2 to produce 2 moles of MgI2. To find the mass of MgI2 produced, we need to calculate the moles of Mg and I2 and then use the mole ratio to determine the moles of MgI2. Finally, we can convert the moles of MgI2 to grams using the molar mass of MgI2.

Given: m(Mg) = 5.15 g, m(I2) = 50.0 g

Molar mass of MgI2 = 278.113 g/mol

1. Calculate the moles of Mg using the formula: moles = mass/molar mass
2. Calculate the moles of I2 using the same formula
3. From the balanced equation, the mole ratio between Mg and MgI2 is 2:2, so the moles of MgI2 will be the same as the moles of Mg
4. Convert the moles of MgI2 to grams using the formula: mass = moles x molar mass

Using these steps, you can determine the mass of MgI2 that can be produced from the given masses of Mg and I2.

Answer 2

54.8 g of MgI2 can be produced. To solve this, you need to determine the molar mass of each reactant and the product. First, look up the atomic weights of iodine and magnesium Atomic weight of Iodine = 126.90447 Atomic weight of Magnesium = 24.305 Molar mass of MgI2 = 24.305 + 2 * 126.90447 = 278.11394 Now determine how many moles of Iodine and Magnesium you have moles of Iodine = 50.0 g / 126.90447 g/mol = 0.393997154 mole moles of Magnesium = 5.15 / 24.305 g/mol = 0.211890557 mole Since for every magnesium atom, you need 2 iodine atoms and since the number of moles of available iodine isn't at least 2 times the available moles of magnesium, iodine is the limiting reagent. So figure out how many moles of magnesium will be consumed by the iodine 0.393997154 mole / 2 = 0.196998577 mole. This means that you can make 0.196998577 moles of MgI2. Now simply multiply by the previously calculated molar mass of MgI2 0.196998577 mole * 278.11394 g/mole = 54.78805 g Round the result to the correct number of significant figures. 54.78805 g = 54.8 g