111,447 views
20 votes
20 votes
I was hopping for help on the photo attached above asap

I was hopping for help on the photo attached above asap-example-1
User Punchman
by
3.0k points

1 Answer

24 votes
24 votes

In this problem, we are comparing the length of the Crazy Ant to the length of the Green anole.

Since we want to know how many times greater than anole is compared to the ant, we can use division to help us:


\text{ Crazy Ant}*\text{ something}=\text{ Green Anole}

To find this, we can simply divide the Green Anoze's length by the Crazy Ant's length


\frac{\text{ Green Anole}}{\text{ Crazy Ant}}=(6)/((3)/(32))

Rewriting this, we have


6/(3)/(32)

Using fraction division, we get


6/(3)/(32)=6*(32)/(3)

Now we can cross cancel 6 and 3:


\cancel{6}2*\frac{32}{\cancel{3}}=2*32

Simplify:


2*32=64

So, the correct answer is I. 64.

User Joliejuly
by
2.7k points