Question

The area of a rectangle is 52in^2 the length of the rectangle is 9 in longer than the width what is the width

Answer 1

Area (A)= 52in^2
Width(W)=?
Length (L) = W+9

Area= LxW
52=(W+9)(W)
52=W^2+ 9W
0= W^2 +9W-52
0=(W+13)(W-4)
W+13=0 then W=-13 and W-4=0 then W=4
We will only use the positive solution of 4 since distance is positive.
W=4