Question

How far will the body fall at t=6 and t=6.2?

Answer 1

EXPLANATION

Given the falling body equation:

`h=16t^2`

Substituting for t=6:

`h=16\cdot6^2=`

Computing the power:

`h=16\cdot36`

Multiplying numbers:

`h=576\text{ ft}`

Now, substituting for t=6.2:

`h=16\cdot(6.2)^2`

Computing the power:

`h=16\cdot38.44`

Multiplying numbers:

`h=615.04\text{ ft}`

Hence, the solutions are:

For t= 6s ---> h=576 ft

For t= 6.2s ---> h= 615.04 ft

Subtracting both distances:

`\Delta h=615.04-576=39.04_{\text{ }}ft`

Hence, the body will fall ≈ 39 ft between those seconds.