1. 6 (a+2)
2. 6a+12
3. 3 (2a+4)
Apply distributive property to solve 1. and 3.
1.
6(a)+6(2) = 6a+12
3. 3(2a)+3(4) = 6a+12
So, expressions 1,2,and 3 are equivalent.
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