Question

The circle below is centered at (10,4) and has a radius of 4. What is itsequation?A. (x-4)2 + (y-10)2 = 16B. (x-4)2 + (y-10)2 = 4C. (x-10)2 + (y - 4)2 = 16D. (X-10)2 + (7-4)2 = 4

Answer 1

The standard equation of a circle with radius r centered at (h,k) is:

`(x-h)^2+(y-k)^2=r^2`

To find the equation of the given circle, substitute r=4 and (h,k)=(10,4):

`\begin{gathered} (x-10)^2+(y-4)^2=4^2 \\ \Rightarrow(x-10)^2+(y-4)^2=16 \end{gathered}`

Therefore, the answer is:

`\begin{gathered} C) \\ (x-10)^2+(y-4)^2=16 \end{gathered}`