224,219 views
31 votes
31 votes
Two containers designed to hold water are side by side, both in the shape of acylinder. Container A has a radius of 6 feet and a height of 16 feet. Container B has aradius of 7 feet and a height of 14 feet. Container A is full of water and the water ispumped into Container B until Container A is empty.To the nearest tenth, what is the percent of Container B that is full after the pumpingis complete?playContainer AContainer B-7h.Submit AnswerAnswer:

Two containers designed to hold water are side by side, both in the shape of acylinder-example-1
User Mutsumi
by
2.7k points

1 Answer

29 votes
29 votes

Let's find the volume of each container

The volume of the container A is:


\begin{gathered} Va=\pi\cdot ra^2\cdot ha \\ where\colon \\ ra=6 \\ ha=16 \\ Va=\pi\cdot(6^2)\cdot16 \\ Va=576\pi ft^3 \end{gathered}

The volume of the container B is:


\begin{gathered} Vb=\pi\cdot rb^2\cdot hb \\ where\colon \\ rb=7 \\ hb=14 \\ Vb=\pi\cdot(7^2)\cdot(14) \\ Vb=686\pi ft^3 \end{gathered}

Let:

x = percent of container B that is full after the pumping is complete:


\begin{gathered} x\cdot Vb=Va \\ x=(Va)/(Vb) \\ x=(576\pi)/(686\pi) \\ x=0.836 \end{gathered}

to the nearest tenth:

84.0%

User Alrodi
by
3.4k points