Given,
Time duration to reach the 1st city, t₁=55.0 min
The speed at which the driver drove to 1st city, s₁=65.0 km/h
Time duration to reach the 2nd city, t₂=16.0 min
The speed at which the driver drove to 2nd city, s₂=70 km/hr
Time duration to reach the 3rd city, t₃=60.0 min
The speed at which the driver drove to 3rd city, s₃=45.0 km/hr
The time spent for lunch and buying gas, t₄=20.0 min
The speed of an object is given by,
Thus the distance traveled by the object is given by,
The distance between the 1st pairs of the city is given by
On substituting the known values,
Distance between the second pair of the cities is,
The distance between the 3rd pair of cities is
(a) The average speed is defined as the total distance divided by the total time taken.
Therefore the average speed of the whole trip is calculated as
On substituting the known values in the above equation,
Therefore the average speed of the trip is 48.91 km
(b) The distance between the initial and the final cities is given by,
On substituting the known values in the above equation,
Therefore the total distance between the initial and the final cities is 123.25 km