Question

what is the final velocity of a 0.152 kg t-ball that has a force of 10 N applied for 0.18 seconds starting from rest?

Answer 1

Given:

The mass of the ball is m =0.152 kg

The force applied to the ball is F = 10 N

The initial velocity of the ball is

`v_(_i)=0\text{ m/s}`

The time taken is t = 0.18 s.

To find the final velocity of the ball.

Step-by-step explanation:

The acceleration can be calculated as

`\begin{gathered} a=(F)/(m) \\ =(10)/(0.152) \\ =65.789\text{ m/s}^2 \end{gathered}`

The final velocity of the ball will be

`\begin{gathered} v_f=v_i+at \\ =0+65.789*0.18 \\ =\text{ 11.84 m/s} \end{gathered}`

Thus, the final velocity is 11.84 m/s.