Given:
it is given that a line passes through the point (1/8,−7) and is perpendicular to the line 5y + 4x = 4.
Find:
we have to find the equation of the line.
Step-by-step explanation:
we know the product of slopes of two per pendicular lines = -1
let m be the slope of the equation, which is perpendicular to 5y + 4x = 4.
Now, the slope of 5y + 4x = 4 is = = - Coefficient of x/coefficient of y = -4/5
since, the product of slopes of two per pendicular lines = -1
Therefore, m * (-4/5) = -1
m = 5/4
Equation of required line passing through (1/8, -7) is
(y - (-7)) = (5/4) (x - (1/8)
32(y + 7) = 5( 8x - 1)
32y + 224 = 40x - 5
32y - 40x = -5 - 224
32y - 40x = -229
Therefore, equation of the line is 32y - 40x = -229