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Determine the equation of the line that passes through the point (1/8,−7) and is perpendicular to the line 5y+4x=4.

User Jon Kartago Lamida
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1 Answer

11 votes
11 votes

Given:

it is given that a line passes through the point (1/8,−7) and is perpendicular to the line 5y + 4x = 4.

Find:

we have to find the equation of the line.

Step-by-step explanation:

we know the product of slopes of two per pendicular lines = -1

let m be the slope of the equation, which is perpendicular to 5y + 4x = 4.

Now, the slope of 5y + 4x = 4 is = = - Coefficient of x/coefficient of y = -4/5

since, the product of slopes of two per pendicular lines = -1

Therefore, m * (-4/5) = -1

m = 5/4

Equation of required line passing through (1/8, -7) is

(y - (-7)) = (5/4) (x - (1/8)

32(y + 7) = 5( 8x - 1)

32y + 224 = 40x - 5

32y - 40x = -5 - 224

32y - 40x = -229

Therefore, equation of the line is 32y - 40x = -229

User Blendi
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2.6k points
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