Question

1. Determine the magnitude of thecentripetal acceleration of a car going 12 m/s (about 27 mi/h) on a circular cloverleaf with a radius of 50 m.

Answer 1

The magnitude of the centripetal acceleration of the car is 2.88 m/s².

Step-by-step explanation:

The centripetal acceleration of a car can be calculated using the formula:

ac = v2 / r

where ac is the centripetal acceleration, v is the velocity of the car, and r is the radius of the circular cloverleaf.

Plugging in the given values, we have:
ac = (12 m/s)2 / 50 m = 2.88 m/s²

Therefore, the magnitude of the centripetal acceleration of the car is 2.88 m/s².

Answer 2

Answer:

The centripetal acceleration = 2.88 m/s²

Explanations:

The speed of the car, v = 12 m/s

The radius of the circular cloverleaf, r = 50 m

The centripetal acceleration (a) is given by the formula:

`a\text{ = }(v^2)/(r)`

Substituting v = 12 m/s and r = 50m into the formula above:

`\begin{gathered} a\text{ = }(12^2)/(50) \\ a\text{ = }(144)/(50) \\ a\text{ = }2.88m/s^2 \end{gathered}`

The centripetal acceleration = 2.88 m/s²