Question

May I please get help with this for I have tried my times but still could not get them right?

Answer 1

`d=\frac{4}{\sqrt[]{3}},c=8\sqrt[]{2}`

Step-by-step explanation:

Use the trigonometric ratio,

`\sin \theta^{}=\frac{Opposite\text{ side}}{Hypotenuse}`

From the first right angled triangle,

`\begin{gathered} \sin 60^o=(2)/(d) \\ d=(2)/(\sin60^o) \\ =\frac{2}{\frac{\sqrt[]{3}}{2}} \\ =\frac{4}{\sqrt[]{3}} \end{gathered}`

Similarly, from the second right angled triangle,

`\begin{gathered} \sin 45^o=(8)/(c) \\ c=(8)/(\sin 45^o) \\ =\frac{8}{\frac{1}{\sqrt[]{2}}} \\ =8\sqrt[]{2} \end{gathered}`