Question

Calculate the moles and the mass of solute in 250.0 ml of 6.00 m naoh

Answer 1

If it is 6.00 M (molar) NaOH, there are 6 moles per liter. Use this equation to find the amount of moles in 250 mL

Molarity x Liters = Moles

We have the molarity already (6.00 M), so we just need to convert mL to L.

250 mL x 1 Liter/1000 mL = .25 L

Set up the equation

6.00 M x .25 L = 1.5 moles

Answer 2

Step-by-step explanation:

As molarity is the number of moles present in liter of solution. So, convert given volume into liter as follows.

`250 ml * (1 L)/(1000 ml)` (as 1 L = 1000 ml)

= 0.25 L

Therefore, number of moles of solute present will be calculated as follows.

Molarity =
`\frac{\text{no. of moles}}{volume}`

6.00 M =
`\frac{\text{no. of moles}}{0.25 L}`

no. of moles = 1.5 mol

Hence, number of moles of solute in 250.0 ml of 6.00 M NaOH is 1.5 mol.

Now, calculate the mass of solute as follows.

No. of moles =
`\frac{mass}{\text{molar mass}}`

1.5 mol =
`(mass)/(39.99 g/mol)`

mass = 59.98 g

Thus, we can conclude that mass of solute in 250.0 ml of 6.00 M NaOH is 59.98 g.