Question

Find the product of -6 + 10i and its complex conjugate.Write your answer in the form a + bi.

Answer 1

`\begin{gathered} 136+(0)i \\ a=136 \\ b=0 \end{gathered}`

Step-by-step explanation:

Given the complex number;

`-6+10i`

Its complex conjugate is;

`-6-10i`

The product of the two complex number is;

`\begin{gathered} (-6+10i)(-6-10i)=-6(-6)-6(-10i)+10i(-6)+10i(-10i) \\ (-6+10i)(-6-10i)=+36+60i-60i-100i^2 \\ (-6+10i)(-6-10i)=+36-100(-1) \\ (-6+10i)(-6-10i)=+36+100 \\ (-6+10i)(-6-10i)=136 \end{gathered}`

Writiing it in the form a + bi, we have;

`\begin{gathered} 136+(0)i \\ a=136 \\ b=0 \end{gathered}`