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Calculate the molarity of a solution containing 0.65 moles of NaCI in 3.50 L of solution

Calculate the molarity of a solution containing 0.65 moles of NaCI in 3.50 L of solution-example-1
User Adarsh Sreeram
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1 Answer

12 votes
12 votes

Answer:

The molarity of the solution is 0.19M. (first option)

Step-by-step explanation:

The given information from the exercise is:

- Moles of NaCl (n): 0.65 moles

- Volume of solution (V): 3.50L

To calculate the molarity of the solution we have to replace the values of n and V in the Molarity formula:


\begin{gathered} M=\frac{n\text{ \lparen moles of solute\rparen}}{V(volume\text{ of solution})} \\ M=(0.65moles)/(3.50L) \\ M=0.19M \end{gathered}

So, the molarity of the solution is 0.19M.

User Akshata Bhat
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