Question

Perform the indicated operations and write the result in the form of a + bi
(3 - 2i)(4 + 3i)

Answer 1

Answer:i=√-1

i²=(√-1)(√-1)=-1

(3-2i)(4+3i)=

=(3*4)+(3*3i)+(-2i*4)+(-2i*3i)

=12+9i-8i-6i²

=12+(9i-8i)-(6*-1)

=12+i+6

=18+i

Answer: (3-2i)(4+.3i)=(18+i)

Explanation:

Answer 2

Remember:
i=√-1
i²=(√-1)(√-1)=-1


(3-2i)(4+3i)=
=(3*4)+(3*3i)+(-2i*4)+(-2i*3i)
=12+9i-8i-6i²
=12+(9i-8i)-(6*-1)
=12+i+6
=18+i

Answer: (3-2i)(4+.3i)=(18+i)