Question

3.6 x 10^23 molecules of copper (i) nitrate to grams

Answer 1

1) Compound: Copper (I) nitrate.

`CuNO_3`

2) Convert molecules of CuNO3 to moles of CuNO3.

Avogadro's number is 6.022*10^23.

1 mol is equal to 6.022*10^23 molecules.

`mol\text{ }CuNO_3=3.6\ast10^(23)\ast\frac{1\text{ }mol}{6.022\ast10^(23)\text{ }molecules}=0.5978\text{ }mol\text{ }CuNO_3`

3) Convert moles of CuNO3 to grams of CuNO3.

The molar mass of CuNO3 is 125.5509 g/mol.

`g\text{ }CuNO_3=0.5978\text{ }mol\text{ }CuNO_3\ast\frac{125.5509\text{ }g\text{ }CuNO_3}{1\text{ }mol\text{ }CuNO_3}=75.05\text{ }g\text{ }CuNO_3`

3.6*10^23 molecules of copper (I) nitrate are equal to 75.05 g CuNO3.

.