Question

S =The maximum walking speed S, in feet per second, of an animal can be modeled by the equationVgL, where g = 32 ft/sec and L is the length, in feet, of the animal's leg. To the nearesthundredth, how many times greater is the maximum walking speed of a giraffe with a leg length of 6feet than a hippopotamus with a leg length of 3 feet?1.41 times2.00 times0.71 times4.06 times

Answer 1

1.41 times

1) Well, let's get started by writing out the equation:

`S=\sqrt[]{gL}`

2) Let's find out the maximum walking speed of a giraffe, plugging into that the given data: Giraffe Leg Length: 6

`\begin{gathered} S_{\text{giraffe}}=\sqrt[]{32*6} \\ S_{\text{giraffe}}=\sqrt[]{192}\approx13.86 \end{gathered}`

And the hippotamus:

`S_{\text{hippo}}=\sqrt[]{32*3}\Rightarrow\sqrt[]{96}\approx9.80`

And now how many times greater by dividing the giraffe's speed by the hippopotamus speed:

`(13.86)/(9.8)\approx1.41`

Hence, the answer is 1.41 times.