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What is the value of x in the equation 1/5 x-2/3 y=30 when y =15

User Sunmoon
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2 Answers

2 votes
The answer: x = 200 .
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Step-by-step explanation:
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Given the equation:
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(1/5)x - (2/3)y = 30 ;

What is the value of "x" when "y" = 15 ?
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Plug in "15" for "y" into the equation; and solve:

(1/5)x - (2/3)*15 = 30 ;

Note:
(2)/(3)*( (15)/(1)) = (2*15)/(3*1) = (30)/(3) = 10 ;


OR: image
[tex] (2)/(1) * (5)/(1) = (2*5)/(1*1) = (10)/(1) = 10 ; " src="
image

Or: [tex] \frac{2}{1} * \frac{5}{1} = 2 * 5 ; (since 2/1 = 2; and since 5/1 = 6 ;

→ 2 * 5 = 10 ;
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So, we can rewrite the equation:
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(1/5)x - (2/3)y = 30 ; and replace "(2/3)y" with "10") ;

(1/5)x - 10 = 30 ;

Add "10" to EACH SIDE of the equation;

(1/5)x - 10 + 10 = 30 + 10 ;

to get: (1/5)x = 40 ;

Now, multiply EACH SIDE of the equation by "5" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
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5* (1/5)x = 40 * 5 ;

x = 200 ;
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The answer: x = 200 .
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User Vitalicus
by
8.2k points
4 votes
First replace y with 15.
1/5x-10=30
Then just solve from there.
x=200
User Secreal
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8.6k points