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25 votes
25 votes
3kIf f(x) = 3 – 222, evaluate [f5k=1

User Christoph Sommer
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1 Answer

11 votes
11 votes

Answer

Step-by-step explanation:

To know the answer we need to sum each value of f(k/5) from k equal to 1 to k equal to 3. So, using the equation f(x) = 3 - 2x², we can complete the following table:

k k/5 f(k/5) = 3 - 2x² value

1 1/5 = 0.2 f(0.2) = 3 - 2(0.2)² 2.92

2 2/5 = 0.4 f(0.4) = 3 - 2(0.4)² 2.68

3 3/5 = 0.6 f(0.6) = 3 - 2(0.6)² 2.28

Therefore, the value for each term of k are:

f(1/5) = 2.92

f(2/5) = 2.68

f(3/5) = 2.28

So, the answer will be the sum of these values, then:

f(1/5) + f(2/5) + f(3/5) = 2.92 + 2.68 + 2.28

f(1/5) + f(2/5) + f(3/5) = 7.88

User Gouldos
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