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2 votes
What is v^4-1 simplified

User Vibhas
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2 Answers

4 votes

\bf \textit{difference of squares} \\ \quad \\ (a-b)(a+b) = a^2-b^2\qquad \qquad a^2-b^2 = (a-b)(a+b)\\\\ -------------------------------\\\\ v^4-1\implies v^4-1^4\implies (v^2)^2-(1^2)^2\implies \underline{(v^2-1^2)}(v^2+1^2) \\\\\\ \underline{(v-1)(v+1)}(v^2+1^2)
User Behzad Bahmanyar
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8.2k points
3 votes
The answer is:
(v-1)(v+1)(v^2+1)
User Keto
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