Question

Which quadratic function has a leading coefficient of 2 and a constant term of –3? f(x) = 2x3 – 3 f(x) = –3x2 – 3x + 2 f(x) = –3x3 + 2 f(x) = 2x2 + 3x – 3

Answer 1

coefficient of 2 and a constant term of –3

answer is

f(x) = 2x^3 – 3

Answer 2

`f(x)=2x^(3) -3`

`f(x)=2x^(2)+3x-3`

Explanation:

Verify each case

case A) we have

`f(x)=2x^(3) -3`

The leading coefficient is
`2`

The constant term is
`-3`

case B) we have

`f(x)=-3x^(2) -3x+2`

The leading coefficient is
`-3`

The constant term is
`2`

case C) we have

`f(x)=-3x^(3)+2`

The leading coefficient is
`-3`

The constant term is
`2`

case D) we have

`f(x)=2x^(2)+3x-3`

The leading coefficient is
`2`

The constant term is
`-3`