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Find the length of a rectangular lot with a perimeter of 72m if the length is 6m more than The Width
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Find the length of a rectangular lot with a perimeter of 72m if the length is 6m more than The Width

User Kick
by
8.4k points

2 Answers

2 votes
First write down what we know...
l = w + 6
perimeter = 2l + 2w = 72
2l + 2w = 72
l + w = 36

Substitute l with (w + 6)...
(w + 6) + w = 36
2w + 6 = 36
2w = 30
w = 15

Width is 15m, so that means the Length is 21m.
User Gabriela
by
7.3k points
5 votes
the width is 15 and length is 21m
User WaterFox
by
8.2k points
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