She spends $(6x + 13) on electricity and rent
so rent + electricity = (6x + 13)
she spends $(3x - 7) on rent
so
$(3x-7) + electricity = $(6x+13)
electricity = $(6x+13) - $(3x-7)
electricity = 6x - 3x +13 +7 =3x +20
she spends $(3x+20) on electricity
for the values of X for which the amount the she spends on electricity is less than $100 we eqate the value of electricity to $100
so $(3x +20) = 100
3x =100 -20
3x =80
x = 80/3= 26.66667
so values of x for which the amount she spends on electricity is less than x lie in the range x<26.6666667
The idea here lies in the fact that they are looking for values of x u put in the equation that gives you less than 100 dollars
put values less than 26.6666667,say 26.666666 in the expression $(3x + 20)
it will give you a value less than $100.
you can check it out