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A 0.90 kg rock is attached to a 0.35 m rope and spun in a vertical circle. The tension on the rope when the rock is at the top of the swing is 76.0 N [down]. What is the speed of the rock?

1 Answer

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76 + 0.90*9.81 =[{ 0.90*(v^2)}/0.35] or
v^2 = (0.35)*[{(76)/0.90} + 9.81] = 94.25 or v = 9.7 m/s
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