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Identify the horizontal asymptote of f(x) =6x-7/11x+8

2 Answers

4 votes
the horizontal asymptote would be y=
(6)/(11)
User Canis Majoris
by
7.8k points
4 votes

Answer:


y=(6)/(11)

Explanation:

The given rational function is


f(x)=(6x-7)/(11x+8)

For the rational function, the horizontal asymptote is given by


y=\frac{\text{Leading coefficient of numerator}}{\text{Leading coefficient of denominator}}

Leading coefficient is the coefficient of the highest exponent.

Leading coefficient of numerator = 6

Leading coefficient of denominator = 11

Therefore, the horizontal asymptote is given by


y=(6)/(11)

User Bimalesh Jha
by
7.8k points