80.8k views
21 votes
Solve the system of equations using elimination. How many solutions does the system have?

15j + 12k = 18
5j + 4k = 6
Responses

A. One solution, j = 3, k = 3

B. No solution

C. One solution, j = 10, k = 8

D. Infinitely many solutions

User Kotoj
by
5.1k points

1 Answer

0 votes

Answer:

I hope it helps u

Explanation:

Let's solve your system by elimination.

15j+12k=18;5j+4k=6

Multiply the second equation by -3, then add the equations together.

(15j+12k=18)

āˆ’3(5j+4k=6)

Becomes:

15j+12k=18

āˆ’15jāˆ’12k=āˆ’18

Add these equations to eliminate j:

0=0

Answer:

Infinitely many solutions

Note: Please Brain-list it ok dear!

If u have any doubt you can ask ok

User Francesca Nannizzi
by
5.1k points