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A survey indicates that for each trip to a supermarket, a shopper spends an average of 43 minutes with a standard deviation of 12 minutes in the store. The lengths of time spent in the store are normally distributed and are represented by the variable X. A shopper enters the store. Find the probability that the shopper will be in the store for each interval of time listed below. A) Find the probability that the shopper will be in the store between 33 and 66 minutes.B) Find the probability that the shopper will be in the store for more than 39 minutes. Hint: Convert the normal distribution X to Standard normal using Z formula Z=(X-μ)/σ and then look the Z-values from the table and then find the probability.Hint: Convert the normal distribution X to Standard normal using Z formula Z=(X-μ)/σ and then look the Z-values from the table and then find the probability.Please help me step-by-step I’m very confused how to insert the numbers when to use a greater than less than sign when to put parentheses I am a 61-year-old woman who hasn’t been in math in three decades please help with this exercise I have a GED test nine days.Please do step-by-step so I can understand how to do the problem and I know I can practice other exercises just like this one

A survey indicates that for each trip to a supermarket, a shopper spends an average-example-1
User Xtremist
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1 Answer

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12 votes

A) We need to find the probability that the shopper will be in the store between 33 and 66 minutes.

We know that the lengths of time spent in the store, x, are normally distributed, with a mean of 43 minutes and a standard deviation of 12 minutes.

Thus, we have:


\begin{gathered} P(33Now, using a z-score table, we obtain:[tex]P(33<strong>B) </strong>We need to find the probability that the shopper will be in the store for more than 39 minutes.<p></p><p>This is given by:</p>[tex]\begin{gathered} P(x>39)=1-P(x<39) \\ \\ P(x\gt39)=1-P\left(z<(39-43)/(12)\right) \\ \\ P(x\gt39)=1-P\left(z<-(4)/(12)\right) \\ \\ P(x\gt39)\cong1-P\left(z<-0.3333\right) \\ \\ P(x\gt39)\cong1-0.36944 \\ \\ P(x\gt39)\cong0.63 \end{gathered}

Answer

A) 0.77

B) 0.63

User Pben
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