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How to completely factor 3u^4x^4-48x^4

User KLI
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2 Answers

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Final answer:

To completely factor the expression 3u^4x^4-48x^4, identify and factor out the greatest common factor, then factor the difference of squares to arrive at the final factored form 3x^4(u^2+4)(u+2)(u-2).

Step-by-step explanation:

To completely factor the expression 3u^4x^4-48x^4, we first look for common factors in both terms. We can see that 3 and x^4 are common to both terms, so we can begin by factoring them out.

This gives us:

3x^4(u^4-16)

Looking at the second term inside the parentheses, u^4-16, we recognize it as a difference of squares because it can be written as u^4-4^2. This allows us to factor it further:

3x^4(u^2+4)(u^2-4)

Again, we have a difference of squares with u^2-4, which can be factored as (u+2)(u-2). Thus, our final factored form of the expression is:

3x^4(u^2+4)(u+2)(u-2)

Remember, when factoring, look for common factors and recognize special products such as a difference of squares.

User TheGeoff
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4 votes
iam sorry if its wrong but i didnt get anything for it 
User Leo Antunes
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