Question

At 80 °C, the volume of a gas is 38.6 mL. At the same pressure, its volume is 244 mL at what temperature?O a. 2000Ob. 2232.35O c. 230O d.-220

Answer 1

The temperature is 2,231.36 K. (The closest value is 2,232.35K).

Step-by-step explanation:

The given information from the exercise is:

- Initial temperature (T1): 80°C (353K)

- Initial volume (V1): 38.6mL

- Final volume (V2): 244mL

1st) It is necessary to convert the temperature unit from °C to K:

80+273 = 353K

2nd) Now we can calculate the final temperature (T2), by replacing the values of T1, V1 and V2 in the Charles's law formula:

`\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ (38.6mL)/(353K)=(244mL)/(T_2) \\ 0.10935(mL)/(K)=(244mL)/(T_2) \\ T_2=(244mL)/(0.10935(mL)/(K)) \\ T_2=2,231.36K \end{gathered}`

So, the temperature is 2,231.36 K. (The closest value is 2,232.35K).