Question

Consider the expression . When using the inspection method, the number you would add to (and subtract from) the constant term of the numerator so the polynomial in the numerator will have (x + 3) as a factor is

Answer 1

(x+3)(x+k) = x^2 + (3+k)x + 3k



3+k=1



k=-2



(x+3)(x-2) = x^2 + x - 6



(x^2 + x - 6) - (x^2 + x - 10) = 4



add 4.