Question

The equation of the straight line passes through the point (0,2) and has a gradient of 1/3 is????

Answer 1

Step-by-step explanation

• Slope-Intercept

`y = mx + b \\ m = slope /gradient \\b = y - intercept`

Substitute m = 1/3 in the equation.

`y = (1)/(3) x + b`

• Substitute the given coordinate point then solve the equation for b-term.

`(x,y) = (0,2)`

`2 = (1)/(3) (0) + b \\ 2 = 0 + b \\ 2 = b`

• Rewrite the equation by substituting the b-value.

`y = (1)/(3) x + 2`

Answer

`\large \boxed{y = (1)/(3) x + 2}`

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