Question

Answer question number 1. The question is in the image.

Answer 1

Step-by-step explanation

Given the function:

`f(x)=2\sin x`

we can choose any value between the interval –2π < x < 2π. For example, –π, –π/2, 0, π/2, and π.

• x = –,π

`f(\pi)=2\sin(\pi)=2\cdot0=0`

The coordinate is (–π, 0).

• x = –,π/2

`f(-(\pi)/(2))=2\sin(-(\pi)/(2))=2\cdot-1=-2`

The coordinate is (–π/2, –2).

• x = 0

`f(0)=2\cdot\sin(0)=2\cdot0=0`

The coordinate is (0, 0).

• x = ,π/2

`f((\pi)/(2))=2\cdot\sin((\pi)/(2))=2\cdot1=2`

The coordinate is (π/2, 2).

• x = ,π

`f(\pi)=2\cdot\sin(\pi)=2\cdot0=0`

The coordinate is (π, 0).

Answer

Thus, our table of values is:

Finally, graphing the points calculated in the table: