From the diagram given,
when you have two triangles like this:
The crossing strokes on AB and PR indicate that both lines are the same in length.
i.e. AB = PR
When you have tiny arcs like we see in
With this information, we can therefore solve the question.
From the question,
AC = AD (single stroke lines)
BC = DE (double stroke lines)
Now there is a theorem that states that "When two sides of a triangle are equal to two sides of another triangle, then the third side of both triangles are necessarily equal"
Therefore, we can conclude that
AB = AE
Thus, the 3 sides of both triangles are equal. Thus SSS is a solution.
Now we can also see that both triangles have the same arc at
Thus, As such, we can also conclude that since angle is equal and we know at least 2 sides are equal, then
SAS is another solution.
Thus the final answer is: Both Apply