Question

If f(x) = log2(x+4), what is f-1(3)

Answer 1

F^-1(3)= 2^3-4=8-4=4
Hope this helps.

Answer 2

imma just solve for f⁻¹(x) for this one

to solve fr the invers
replace f(x) with y
switch x and y
solve for y
replace y with f⁻¹(x)

I'm assuming your thing is
`f(x)=log_2(x+4)`

remember


`log_a(b)=c` translates to
`a^c=b`

so
if we replace y with f(x)

`y=log_2(x+4)`
switch

`x=log_2(y+4)`
translate

`2^x=y+4`
minus 4

`2^x-4=y`

`f^(-1)(x)=2^x-4`
evaluate

`f^(-1)(3)=2^3-4`

`f^(-1)(3)=8-4`

`[f^(-1)(3)=4`

it equals 4