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Find the length of the side of a regular hexagon inscribed in a circle whose radius is 10 cm?

User Rudolf Morkovskyi
by
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1 Answer

23 votes
23 votes

Given

regular hexagon inscribed in a circle whose radius is 10 cm

Answer

Let a regular hexagon ABCDEF is inscribed in a circle of radius 10cm and

center O. Join O to A and O to B

In triangle OAB angle AOB=360°/6=60°.

and OA=OB= r=10cm (given) thus , angle OAB=angle OBA=x°(let)

angle OAB+angle OBA+angle AOB=180°

or x°+x°+60°=180°

or 2x°=180°-60°=120°

or. x=120°/2=60° , or angle OAB=angle OBA=angle AOB=60°.

thus ,triangle OAB is an equilateral triangle.

AB=OA =OB =10cm

User Garth
by
3.0k points
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