Question

What are the new vertices of quadrilateral ABCD if the quadrilateral is reflected across the x-axis? A. A = (-4,-5), B' = (2,-5), C = (5,-1), D' = (-2,-1) B. A = (-5,-4), B' = (-5,2), C' = (–1,5), D' = (-1,-2) C. A = (4,-5), B' = (-2,-5), C' = (-5,–1), D' = (2,-1) D. A' = (4,5), B' = (-2,5), C = (-5,1), D' = (2,1)

Answer 1

A)

A'=(-4,-5)

B'=(2,-5)

C'=(5,-1)

D=(-2,-1)

Step-by-step explanation

Step 1

when you have a reflection across the x -axis use the proper rule:

The rule for reflecting over the X axis is to negate the value of the y-coordinate of each point, but leave the x-value the same

`(x,y)\Rightarrow reflection\text{ across x-a}\xi s\Rightarrow(x,-y)`

Let

A=(-4,5)

B=(2,5)

C=(5,1)

D=(-2,1)

Now, apply( change the sign in y coordinate)

A'=(-4,-5)

B'=(2,-5)

C'=(5,-1)

D'=(-2,-1)

graph:

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