Question

A person's heartbeat is 61 beats per minute. If his/her heart beats 3.1e9 times in a lifetime, how long (in whole years) does the person live? Disregard leap years.

Answer 1

The approximate lifespan of the person is 96.79 years based on a heartbeat of 61 beats per minute and 3.1e9 total heartbeats in a lifetime.

Step-by-step explanation:

To calculate the number of years a person lives based on their heartbeat, we can divide the total number of heartbeats in a lifetime by the number of heartbeats per minute. First, let's convert 3.1e9 to standard notation: 3,100,000,000. Then, we divide this number by 61 to find the number of minutes it takes for the person's heart to beat 3.1e9 times. Dividing 3,100,000,000 by 61 gives us approximately 50,819,672.13 minutes. We can then divide this number by the number of minutes in a year (525,600) to find the approximate number of years the person lives. 50,819,672.13 minutes divided by 525,600 gives us approximately 96.79 years.

Answer 2

In this question, you are asked the time but given the speed(61beat/min) and the number of beats(3.1 x 10^9). Then the equation would be:

Time= number of beats/ speed
Time = 3.1 x 10^9 beats / (61 beats/min)= 5.081 x 10^7 minutes.

Then convert it to years, disregard of leap years it would be : 5.081 x 10^7 minutes / (60 minutes/hour) / (24 hour/day) / (365 day/year)= 96.69 years