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Find aRound to the nearest tenth:a10 cm1500120=a = [? ]cmLaw of Sines: sin Asin B.=basin CсEnter

Find aRound to the nearest tenth:a10 cm1500120=a = [? ]cmLaw of Sines: sin Asin B-example-1
User Philz
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1 Answer

22 votes
22 votes

Given

To find the value of a.

Now,

It is given that,


(\sin A)/(a)=(\sin B)/(b)=(\sin C)/(c)

From, the figure the value of B is 10cm.

Therefore,


\begin{gathered} (\sin150\degree)/(a)=(\sin12\degree)/(10) \\ ((1)/(2))/(a)=(0.20791169)/(10) \\ (1)/(2a)=(0.20791169)/(10) \\ (1)/(a)=(0.20791169*2)/(10) \\ (1)/(a)=0.041582338 \\ a=24.04867181 \\ a=24.0(\text{Rounded to nearest 10th, since the digit next to 10th place<5.} \\ a=24.0cm \end{gathered}

Hence the value of a is 24.0cm.

Find aRound to the nearest tenth:a10 cm1500120=a = [? ]cmLaw of Sines: sin Asin B-example-1
User Ajventi
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