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Got stumped on the (7x^2-2) part

Got stumped on the (7x^2-2) part-example-1

1 Answer

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7x²-2=0
add 2 to both sides
7x²=2
divide by 7 both sides

x^2=(2)/(7)
sqrt both sides

x=+/-(√(2))/(√(7))

x=+/-(√(14))/(7)



so the possible values of x are

x=(5)/(2),(-√(14))/(7),(√(14))/(7)
User Jeand
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