Question

Instructions: Solve the following systems of equations algebraically. If there are no real solutions, type “none” in both blanks. If there is only one, type “none” in the other blank.

Answer 1

Okay, here we have this:

Considering the provided system of equations, we are going to find the requested solutions, so we obtain the following:

So since the two equations are equal to y, we will proceed to equal them, we have:

y=-x-10

y=x^2-5x-10

Then:

-x-10=x^2-5x-10

0=x^2-5x+x-10+10

0=x^2-4x

0=x(x-4)

x=0 or x-4=0

x=0 or x=4

We will evaluate to know the values of "y" that are solutions:

x=0:

y=-x-10

y=-0-10

y=-10

x=4:

y=-x-10

y=-4-10

y=-14

Finally we obtain that the solutions are: (0, -10) (4, -14).