A set of 4 consecutive odd integers sums to 32. What is the greatest of these integers?
Let
x -----> the first od integer
x+2 ----> the second odd integer
x+4----> the third odd integer
x+6 ---> the fourth odd integer
we have
x+(x+2)+(x+4)+(x+6)=32
solve for x
4x+12=32
4x=20
x=5
so
x+6=5+6=11
therefore
the answer is 11