Question

Daniel steps on the gas pedal of his car, and the engine increases its performance from zero to

2700 rpms (rotations per minute). What are the frequency and period?
(Hint: frequency is cycles per second.]

Answer 1

The frequency and the period are 45 cycles/second and 0.023 seconds

Step-by-step explanation:

The frequency of the engine is given by :

`f=(rpm)/(60)`

We have, the engine increases its performance from zero to 2700 rpms.

Frequency,

`f=(2700)/(60)\ \text{cycles per second}\\\\f=45\ \text{cycles per second}`

The time period of the engine is given by :

T = f/f

So,

`T=(1)/(45)\ s\\\\T=0.023\ s`

Hence, the required frequency and the period are 45 cycles/second and 0.023 seconds respectively.